-x^2+16x-50=0

Solution for -x^2+16x-50=0 equation:

-x^2+16x-50=0

We add all the numbers together, and all the variables

-1x^2+16x-50=0

a = -1; b = 16; c = -50;
Δ = b2-4ac
Δ = 162-4·(-1)·(-50)
Δ = 56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{56}=\sqrt{4*14}=\sqrt{4}*\sqrt{14}=2\sqrt{14}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-2\sqrt{14}}{2*-1}=\frac{-16-2\sqrt{14}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+2\sqrt{14}}{2*-1}=\frac{-16+2\sqrt{14}}{-2}
$